The angular velocity of second hand, of a clock is :

Question

The angular velocity of second hand, of a clock is : (A) ((π/6)) rad s -1 (B) ((π/60)) rad s -1 (C) ((π/30)) rad s -1 (D) ((π/15)) rad s -1

Tardigrade Admin · Accepted Answer

Angular velocity =(Δ θ/Δ t)=(2 π/60) rad s -1 =(π/30) rad s -1 Reason: A second hand makes an angle of 2 π (i.e., 360° ) is one minute, (i.e., 60 s ).

Q. The angular velocity of second hand, of a clock is :

$(\frac{π}{6}) r a d s^{- 1}$

$(\frac{π}{60}) r a d s^{- 1}$

$(\frac{π}{30}) r a d s^{- 1}$

$(\frac{π}{15}) r a d s^{- 1}$

Angular velocity $= \frac{Δ θ}{Δ t} = \frac{2 π}{60} r a d s^{- 1}$
$= \frac{π}{30} r a d s^{- 1}$
Reason : A second hand makes an angle of $2 π$
(i.e., $36 0^{\circ}$ ) is one minute, (i.e., $60 s$ ).

Q. The angular velocity of second hand, of a clock is :

(6π​)rads−1

(60π​)rads−1

(30π​)rads−1

(15π​)rads−1

Angular velocity =ΔtΔθ​=602π​rads−1 =30π​rads−1 Reason : A second hand makes an angle of 2π (i.e., 360∘ ) is one minute, (i.e., 60s ).

$(\frac{π}{6}) r a d s^{- 1}$

$(\frac{π}{60}) r a d s^{- 1}$

$(\frac{π}{30}) r a d s^{- 1}$

$(\frac{π}{15}) r a d s^{- 1}$

Angular velocity $= \frac{Δ θ}{Δ t} = \frac{2 π}{60} r a d s^{- 1}$
$= \frac{π}{30} r a d s^{- 1}$
Reason : A second hand makes an angle of $2 π$
(i.e., $36 0^{\circ}$ ) is one minute, (i.e., $60 s$ ).