The amplitude of the sinusoidially oscillating electric field of a plane wave is 60 V/m . Then the amplitude of magnetic field is:

Question

The amplitude of the sinusoidially oscillating electric field of a plane wave is 60 V/m . Then the amplitude of magnetic field is: (A)  2× 102T  (B)  6× 107T  (C)  6× 102T  (D)  2× 10-7T

Tardigrade Admin · Accepted Answer

The instantaneous magnitudes of electric field (E) and magnetic field (B) are related as (E/B)=c ⇒ B=(E/c) Given, E=60 V/m,c=3× 108m/s ∴ B=(60/3× 108)=2× 10-7T

Q. The amplitude of the sinusoidially oscillating electric field of a plane wave is $60 V / m$ . Then the amplitude of magnetic field is:

$2 \times 10^{2} T$

$6 \times 10^{7} T$

$6 \times 10^{2} T$

$2 \times 10^{- 7} T$

$3 \times 10^{8} T$

The instantaneous magnitudes of electric field (E) and magnetic field (B) are related as
$\frac{E}{B} = c$ $\Rightarrow$ $B = \frac{E}{c}$
Given, $E = 60 V / m, c = 3 \times 10^{8} m / s$
$∴$ $B = \frac{60}{3 \times 10 ^{8}} = 2 \times 10^{- 7} T$

Q. The amplitude of the sinusoidially oscillating electric field of a plane wave is 60V/m . Then the amplitude of magnetic field is:

2×102T

6×107T

6×102T

2×10−7T

3×108T

The instantaneous magnitudes of electric field (E) and magnetic field (B) are related as BE​=c ⇒ B=cE​ Given, E=60V/m,c=3×108m/s ∴ B=3×10860​=2×10−7T