The instantaneous magnitudes of electric field (E) and magnetic field (B) are related as
$ \frac{E}{B}=c $ $ \Rightarrow $ $ B=\frac{E}{c} $
Given, $ E=60\,V/m,c=3\times {{10}^{8}}m/s $
$ \therefore $ $ B=\frac{60}{3\times {{10}^{8}}}=2\times {{10}^{-7}}T $