The amplitude of a particle due to superposition of following SHMs. Along the same line is X1=2 sin 50 π t ; X2=10 sin (50 π t+37°) X3=-4 sin 50 π t ; X4=-12 cos 50 π t

Question

The amplitude of a particle due to superposition of following SHMs. Along the same line is X1=2 sin 50 π t ; X2=10 sin (50 π t+37°) X3=-4 sin 50 π t ; X4=-12 cos 50 π t (A) 4 √2 (B) 4 (C) 6 √2 (D) None of these

Tardigrade Admin · Accepted Answer

Amplitude phasor diagram after super position of all four SHMs is shown in figure 1 and further simplification in figure- 2 3 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/65abe754c71aaf861f677fcb900f07c7-.png" /> ⇒ Resultant amplitude =6 √2.

Q. The amplitude of a particle due to superposition of following SHMs. Along the same line is $X_{1} = 2 sin 50 π t; X_{2} = 10$ $sin (50 π t + 3 7^{\circ}) X_{3} = - 4 sin 50 π t; X_{4} = - 12 cos 50 π t$

$42$

4

$62$

None of these

Amplitude phasor diagram after super position of all four SHMs is shown in figure 1 and further simplification in figure- $2 & 3$

$\Rightarrow$ Resultant amplitude $= 62$ .

Q. The amplitude of a particle due to superposition of following SHMs. Along the same line is X1​=2sin50πt;X2​=10 sin(50πt+37∘)X3​=−4sin50πt;X4​=−12cos50πt

42​

4

62​

None of these

Amplitude phasor diagram after super position of all four SHMs is shown in figure 1 and further simplification in figure- 2&3 ⇒ Resultant amplitude =62​.

Q. The amplitude of a particle due to superposition of following SHMs. Along the same line is $X_{1} = 2 sin 50 π t; X_{2} = 10$ $sin (50 π t + 3 7^{\circ}) X_{3} = - 4 sin 50 π t; X_{4} = - 12 cos 50 π t$

$42$

$62$

Amplitude phasor diagram after super position of all four SHMs is shown in figure 1 and further simplification in figure- $2 & 3$

$\Rightarrow$ Resultant amplitude $= 62$ .