1. Tardigrade
  2. Question
  3. Physics
  4. The amplitude of a particle due to superposition of following SHMs. Along the same line is X1=2 sin 50 π t ; X2=10 sin (50 π t+37°) X3=-4 sin 50 π t ; X4=-12 cos 50 π t

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The amplitude of a particle due to superposition of following SHMs. Along the same line is $X_{1}=2 \, \sin\, 50\, \pi t ; X_{2}=10$ $\sin \left(50 \pi t+37^{\circ}\right) X_{3}=-4 \, \sin \, 50\, \pi t ; X_{4}=-12 \, \cos \, 50\, \pi t$

Oscillations

Solution:

Amplitude phasor diagram after super position of all four SHMs is shown in figure 1 and further simplification in figure- $2\, \& \, 3$
image
$\Rightarrow $ Resultant amplitude $=6 \sqrt{2}$.