The amount of water that should be added to 500 ml of 0.5 N solution of NaOH to give a concentration of 10 mg per ml is

Question

The amount of water that should be added to 500 ml of 0.5 N solution of NaOH to give a concentration of 10 mg per ml is (A) 100 (B) 200 (C) 250 (D) 500

Tardigrade Admin · Accepted Answer

N1 = 0.5 N → 10 g per ml N2=(10×10-3g/40×1)×1000=0.25 N V1, = 500 ml, V2 = ? N1 V1 = N2V2; 0.5 × 500 = 0.25 × V2 V2 = 1000 ml final volume of water added = 1000 - 500 = 500 mL.

Q. The amount of water that should be added to $500 m l$ of $0.5 N$ solution of $N a O H$ to give a concentration of $10 m g p er m l$ is

$100$

$200$

$250$

$500$

$N_{1} = 0.5 N \to 10 g p er m l$
$N_{2} = \frac{10 \times 1 0 ^{- 3} g}{40 \times 1} \times 1000 = 0.25 N$
$V_{1}, = 500 m l, V_{2} = ?$
$N_{1} V_{1} = N_{2} V_{2}; 0.5 \times 500 = 0.25 \times V_{2}$
$V_{2} = 1000 m l$
final volume of water added $= 1000 - 500 = 500 m L .$

Q. The amount of water that should be added to 500ml of 0.5N solution of NaOH to give a concentration of 10mgperml is

100

200

250

500