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  4. The amount of water that should be added to 500 ml of 0.5 N solution of NaOH to give a concentration of 10 mg per ml is

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Q. The amount of water that should be added to $500\, ml$ of $0.5 \,N$ solution of $NaOH$ to give a concentration of $10\, mg\, per\, ml$ is

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Solution:

$N_1 = 0.5 N \to 10 g\, per\, ml$
$N_{2}=\frac{10\times10^{-3}g}{40\times1}\times1000=0.25 N$
$V_1, = 500 ml, V_2 = ?$
$N_1 V_1 = N_2V_2; 0.5 \times 500 = 0.25 \times V_2$
$V_2\, = \,1000\, ml$
final volume of water added $= 1000 - 500 = 500\, mL.$