The amount of heat evolved when 500 cm3 of 0.1 M HCl is mixed with 200 cm3 of 0.2 M NaOH is

Question

The amount of heat evolved when 500 cm3 of 0.1 M HCl is mixed with 200 cm3 of 0.2 M NaOH is  (A) 1.292 kJ (B) 2.292 kJ (C) 3.392 kJ (D) 0.292 kJ

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/bc787ab788e0052538d2c7a01630d073-.png" /> ∵ In neutralisation of 1 mole of NaOH by 1 mole HCl, heat evolved =57.3 kJ ∴ To neutralise 0.04 mole of NaOH by 0.04 mole of HCl, heat evolved will be =57.3 × 0.04 kJ =2.292 kJ

Q. The amount of heat evolved when $500 c m^{3}$ of $0.1 M H Cl$ is mixed with $200 c m^{3}$ of $0.2 M N a O H$ is _______

$1.292 k J$

$2.292 k J$

$3.392 k J$

$0.292 k J$

$∵$ In neutralisation of 1 mole of $N a O H$ by 1 mole HCl, heat evolved $= 57.3 k J$

$∴$ To neutralise $0.04$ mole of $N a O H$ by

$0.04$ mole of $H Cl,$

heat evolved will be $= 57.3 \times 0.04 k J$

$= 2.292 k J$

Q. The amount of heat evolved when 500cm3 of 0.1MHCl is mixed with 200cm3 of 0.2MNaOH is _______

1.292kJ

2.292kJ

3.392kJ

0.292kJ