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Chemistry
The amount of heat evolved when 500 cm3 of 0.1 M HCl is mixed with 200 cm3 of 0.2 M NaOH is
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Q. The amount of heat evolved when $500 \,cm^3$ of $0.1 \,M \,HCl$ is mixed with $200\, cm^3$ of $0.2\,M \,NaOH$ is _______
KCET
KCET 2010
Some Basic Concepts of Chemistry
A
$1.292\, kJ$
17%
B
$2.292\, kJ$
39%
C
$3.392\, kJ$
25%
D
$0.292\, kJ$
19%
Solution:
$\because$ In neutralisation of 1 mole of $NaOH$ by 1 mole HCl, heat evolved $=57.3\, kJ$
$\therefore $ To neutralise $0.04$ mole of $NaOH$ by
$0.04$ mole of $HCl,$
heat evolved will be $=57.3 \times 0.04\, kJ$
$=2.292\, kJ$