Question

The amount of bromine (in grams) required to convert 2 g of phenol into 2, 4, 6-tribromophenol is

• A. 4.00
• B. 6.00
• C. 10.22
• D. 20.44

Answer 1

Answer: (C)

$PhOH+3B{r}_2\to C_6{H}_{2}B{r}_{3}OH+3HBr$

1 mole 3 moles 1 mole

94 grams of phenol reacts with $480gms$ . of $B{r}_2$

$2$ $gm$ . of phenol $—\frac{480}{94}\times 2=10.22g$