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  4. The amount of bromine (in grams) required to convert 2 g of phenol into 2, 4, 6-tribromophenol is

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Q. The amount of bromine (in grams) required to convert 2 g of phenol into 2, 4, 6-tribromophenol is

NTA AbhyasNTA Abhyas 2020

Solution:

$PhOH+3Br_{2} \rightarrow C_{6}H_{2}Br_{3}OH+3HBr$

1 mole 3 moles 1 mole

94 grams of phenol reacts with $480 \, gms$ . of $Br_{2}$

$2$ $gm$ . of phenol $—\frac{480}{94}\times 2=10.22 \, g$