The alkene formed as a major product in the above elimination reaction is :

Question

The alkene formed as a major product in the above elimination reaction is : (A)  (B) CH2 = CH2 (C)  (D)

Tardigrade Admin · Accepted Answer

There are four p-hydrogens, in this quaternary ammonium salt.
On heating quaternary ammonium salt gives Hofmann elimination (abstraction of most acidic hydrogen which is

β^{1^{'}}

)
Hence major product is

C H_{2} = C H_{2}

. (Least substituted alkene)

Q. The alkene formed as a major product in the above elimination reaction is :

CH2​=CH2​

There are four p-hydrogens, in this quaternary ammonium salt. On heating quaternary ammonium salt gives Hofmann elimination (abstraction of most acidic hydrogen which is β1′) Hence major product is CH2​=CH2​. (Least substituted alkene)

$C H_{2} = C H_{2}$

There are four p-hydrogens, in this quaternary ammonium salt.
On heating quaternary ammonium salt gives Hofmann elimination (abstraction of most acidic hydrogen which is $β^{1^{'}}$ )
Hence major product is $C H_{2} = C H_{2}$ . (Least substituted alkene)