Q.
The alkene formed as a major product in the above elimination reaction is :
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Solution:
There are four p-hydrogens, in this quaternary ammonium salt.
On heating quaternary ammonium salt gives Hofmann elimination (abstraction of most acidic hydrogen which is $\beta^{1'}$)
Hence major product is $CH_{2}=CH_{2}$. (Least substituted alkene)
