Question

The acid catalyzed iodination of propanone represented by equation:
$C{H}_{3}COC{H}_3+I_2\stackrel{\left[H^{+}\right]}{\to }C{H}_{3}COC{H}_{2}I+HI$
is first order w.r.t. $H^{+}$ ion and to propanone and zero order $w.r.t.$ $I_2$ . Then correct graph between rate of reaction $\left[R\right]$ vs $\left[C{H}_{3}COC{H}_3\right]$ .

• A.
• B.
• C.
• D.

Answer 1

Answer: (B)

It becomes pseodo first order reaction