1. Tardigrade
  2. Question
  3. Chemistry
  4. The acid catalyzed iodination of propanone represented by equation: CH3COCH3+I2 overset[H+] arrow CH3COCH2I+HI is first order w.r.t. H+ ion and to propanone and zero order w.r.t. I2 . Then correct graph between rate of reaction [R] vs [CH3 COCH3] .

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Q. The acid catalyzed iodination of propanone represented by equation:
$CH_{3}COCH_{3}+I_{2}\overset{\left[H^{+}\right]}{ \rightarrow }CH_{3}COCH_{2}I+HI$
is first order w.r.t. $H^{+}$ ion and to propanone and zero order $w.r.t.$ $I_{2}$ . Then correct graph between rate of reaction $\left[R\right]$ vs $\left[CH_{3} COCH_{3}\right]$ .

NTA AbhyasNTA Abhyas 2020

Solution:

It becomes pseodo first order reaction