The acceleration-displacement graph of a particle executing simple harmonic motion is shown in the figure. The frequency of oscillation is

Question

The acceleration-displacement graph of a particle executing simple harmonic motion is shown in the figure. The frequency of oscillation is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-ykjtrumek5cfjisg.jpg" /> (A) (√2.5/π ) s- 1 (B) 2π √10s- 1 (C) (1/2 π )√5s- 1 (D) (1/2 π )√20s- 1

Tardigrade Admin · Accepted Answer

Using slope of the curve we can write equation a=-10 x Comparing it with a=-ω 2 x ω 2=10 ω =√10 frequency f=(ω /2 π )=(1/2 π )√10 s- 1

Q. The acceleration-displacement graph of a particle executing simple harmonic motion is shown in the figure. The frequency of oscillation is

$\frac{2.5}{π} s^{- 1}$

$2 π 10 s^{- 1}$

$\frac{1}{2 π} 5 s^{- 1}$

$\frac{1}{2 π} 20 s^{- 1}$

Using slope of the curve we can write equation
$a = - 10 x$
Comparing it with $a = - ω^{2} x$
$ω^{2} = 10$
$ω = 10$
frequency $f = \frac{ω}{2 π} = \frac{1}{2 π} 10 s^{- 1}$

Q. The acceleration-displacement graph of a particle executing simple harmonic motion is shown in the figure. The frequency of oscillation is

π2.5​​s−1

2π10​s−1

2π1​5​s−1

2π1​20​s−1

Using slope of the curve we can write equation a=−10x Comparing it with a=−ω2x ω2=10 ω=10​ frequency f=2πω​=2π1​10​s−1

$\frac{2.5}{π} s^{- 1}$

$2 π 10 s^{- 1}$

$\frac{1}{2 π} 5 s^{- 1}$

$\frac{1}{2 π} 20 s^{- 1}$

Using slope of the curve we can write equation
$a = - 10 x$
Comparing it with $a = - ω^{2} x$
$ω^{2} = 10$
$ω = 10$
frequency $f = \frac{ω}{2 π} = \frac{1}{2 π} 10 s^{- 1}$