Question

The acceleration-displacement graph of a particle executing simple harmonic motion is shown in the figure. The frequency of oscillation is

• A. $\frac{\sqrt{2.5}}{\pi } \, s^{- 1}$
• B. $2\pi \sqrt{10}s^{- 1}$
• C. $\frac{1}{2 \pi }\sqrt{5}s^{- 1}$
• D. $\frac{1}{2 \pi }\sqrt{20}s^{- 1}$

Answer 1

Answer: (A)

Using slope of the curve we can write equation
$a=-10 \, x$
Comparing it with $a=-\omega ^{2 \, }x$
$\omega ^{2}=10$
$\omega =\sqrt{10}$
frequency $f=\frac{\omega }{2 \pi }=\frac{1}{2 \pi }\sqrt{10 \, } \, s^{- 1}$