Tert-butyl bromide on treatment with sodium methoxide yields

Question

Tert-butyl bromide on treatment with sodium methoxide yields (A) sodium tertiary butoxide (B) methyl tertiary butyl ether (C) tert-butyl alcohol (D) iso-butylene.

Tardigrade Admin · Accepted Answer

Tert-butyl bromide first form stable tert-butyl carbonium ion which further stabilises by loss of one proton ( H +) from neighbouring 'C' atom and forms a multiple bond. Thus isobutylene is formed as major product. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/11084e7a3940327554cf655f33ff6f43-.png" />

Q. Tert-butyl bromide on treatment with sodium methoxide yields

sodium tertiary butoxide

methyl tertiary butyl ether

tert-butyl alcohol

iso-butylene.

Tert-butyl bromide first form stable tert-butyl carbonium ion which further stabilises by loss of one proton $(H^{+})$ from neighbouring ' $C$ ' atom and forms a multiple bond. Thus isobutylene is formed as major product.

Q. Tert-butyl bromide on treatment with sodium methoxide yields

sodium tertiary butoxide

methyl tertiary butyl ether

tert-butyl alcohol

iso-butylene.

Tert-butyl bromide first form stable tert-butyl carbonium ion which further stabilises by loss of one proton (H+) from neighbouring 'C' atom and forms a multiple bond. Thus isobutylene is formed as major product.

Tert-butyl bromide first form stable tert-butyl carbonium ion which further stabilises by loss of one proton $(H^{+})$ from neighbouring ' $C$ ' atom and forms a multiple bond. Thus isobutylene is formed as major product.