Question

${\tan }^{-1}\left(\frac{1}{4}\right)+{\tan }^{-1}\left(\frac{2}{9}\right)$ equals to

• A. $\frac{1}{2}{\cos }^{-1}\left(\frac{3}{5}\right)$
• B. $\frac{1}{2}{\sin }^{-1}\left(\frac{3}{5}\right)$
• C. $\frac{1}{2}{\tan }^{-1}\left(\frac{3}{5}\right)$
• D. ${\tan }^{-1}\left(\frac{1}{2}\right)$

Answer 1

Answer: (A), (D)

Correct answer is (a) $\frac{1}{2}{\cos }^{-1}\left(\frac{3}{5}\right)$ Correct answer is (d) ${\tan }^{-1}\left(\frac{1}{2}\right)$