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Q. $\tan ^{-1}\left(\frac{1}{4}\right)+\tan ^{-1}\left(\frac{2}{9}\right)$ equals to

Inverse Trigonometric Functions

Solution:

Correct answer is (a) $\frac{1}{2} \cos ^{-1}\left(\frac{3}{5}\right)$Correct answer is (d) $\tan ^{-1}\left(\frac{1}{2}\right)$