T0 is the time period of a simple pendulum at a place. If the length of the pendulum is reduced to (1/16) times of its initial value, the modified time period is :

Question

T0 is the time period of a simple pendulum at a place. If the length of the pendulum is reduced to (1/16) times of its initial value, the modified time period is : (A) T0 (B) 8 π T0 (C) 4 T0 (D) (1/4) T0

Tardigrade Admin · Accepted Answer

T0=2 π √(l/g) New time period T=2 π √(l/ 16/g) =(2 π/4) √(l/g) T=(T0/4)

Q. $T_{0}$ is the time period of a simple pendulum at a place. If the length of the pendulum is reduced to $\frac{1}{16}$ times of its initial value, the modified time period is :

$T_{0}$

$8 π T_{0}$

$4 T_{0}$

$\frac{1}{4} T_{0}$

$T_{0} = 2 π \frac{l}{g}$
New time period $T = 2 π \frac{l /16}{g}$
$= \frac{2 π}{4} \frac{l}{g}$
$T = \frac{T _{0}}{4}$

Q. T0​ is the time period of a simple pendulum at a place. If the length of the pendulum is reduced to 161​ times of its initial value, the modified time period is :

T0​

8πT0​

4T0​

41​T0​