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Q. $T_{0}$ is the time period of a simple pendulum at a place. If the length of the pendulum is reduced to $\frac {1}{16}$ times of its initial value, the modified time period is :

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Solution:

$T_{0}=2 \pi \sqrt{\frac{l}{g}}$
New time period $T=2 \pi \sqrt{\frac{l/ 16}{g}}$
$=\frac{2 \pi}{4} \sqrt{\frac{l}{g}}$
$T=\frac{T_{0}}{4}$