Suppose that the number of elements in set A is p, the number of elements in set B is q and the number of elements in A × B is 7 then p2+q2=

Question

Suppose that the number of elements in set A is p, the number of elements in set B is q and the number of elements in A × B is 7 then p2+q2= (A) 50 (B) 42 (C) 51 (D) 49

Tardigrade Admin · Accepted Answer

n ( A )= p , n ( B )= q n ( A × B )=7 pq =7 p 2+ q 2=72+12 or 12+72 p 2+ q 2=50

Q. Suppose that the number of elements in set $A$ is $p$ , the number of elements in set $B$ is $q$ and the number of elements in $A \times B$ is $7$ then $p^{2} + q^{2} =$ _____

50

42

51

49

$n (A) = p, n (B) = q$
$n (A \times B) = 7$
$pq = 7$
$p^{2} + q^{2} = 7^{2} + 1^{2}$ or $1^{2} + 7^{2}$
$p^{2} + q^{2} = 50$

Q. Suppose that the number of elements in set A is p, the number of elements in set B is q and the number of elements in A×B is 7 then p2+q2=_____

50

42

51

49

n(A)=p,n(B)=q n(A×B)=7 pq=7 p2+q2=72+12 or 12+72 p2+q2=50

Q. Suppose that the number of elements in set $A$ is $p$ , the number of elements in set $B$ is $q$ and the number of elements in $A \times B$ is $7$ then $p^{2} + q^{2} =$ _____

$n (A) = p, n (B) = q$
$n (A \times B) = 7$
$pq = 7$
$p^{2} + q^{2} = 7^{2} + 1^{2}$ or $1^{2} + 7^{2}$
$p^{2} + q^{2} = 50$