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Mathematics
Suppose that the number of elements in set A is p, the number of elements in set B is q and the number of elements in A × B is 7 then p2+q2=
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Q. Suppose that the number of elements in set $A$ is $p$, the number of elements in set $B$ is $q$ and the number of elements in $A \times B$ is $7$ then $p^{2}+q^{2}=$_____
KCET
KCET 2022
Relations and Functions
A
50
25%
B
42
21%
C
51
13%
D
49
41%
Solution:
$n ( A )= p , n ( B )= q$
$n ( A \times B )=7$
$pq =7$
$p ^{2}+ q ^{2}=7^{2}+1^{2}$ or $1^{2}+7^{2}$
$p ^{2}+ q ^{2}=50$