Suppose that ' a ' and ' b ' are non zero real numbers and the equation x2+a x+b=0 has solutions a and b. Then the pair ( a , b ), is

Question

Suppose that ' a ' and ' b ' are non zero real numbers and the equation x2+a x+b=0 has solutions a and b. Then the pair ( a , b ), is (A) (-2,1) (B) (-1.2) (C) (1,-2) (D) (2,-1)

Tardigrade Admin · Accepted Answer

x2+a x+b=0 a+b=-a ⇒ 2 a+b=0 text and a b=b ⇒ b=0 ( text rejected) ∴ a=1 ; b=-2 ⇒ (1,-2)

Q. Suppose that ' $a$ ' and ' $b$ ' are non zero real numbers and the equation $x^{2} + a x + b = 0$ has solutions $a$ and $b$ . Then the pair $(a, b)$ , is

$(- 2, 1)$

$(- 1.2)$

$(1, - 2)$

$(2, - 1)$

$x^{2} + a x + b = 0$
$a + b = - a \Rightarrow 2 a + b = 0$
$and ab = b \Rightarrow b = 0 (rejected)$
$∴ a = 1; b = - 2 \Rightarrow (1, - 2)$

Q. Suppose that ' a ' and ' b ' are non zero real numbers and the equation x2+ax+b=0 has solutions a and b. Then the pair (a,b), is

(−2,1)

(−1.2)

(1,−2)

(2,−1)