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Q. Suppose that ' $a$ ' and ' $b$ ' are non zero real numbers and the equation $x^2+a x+b=0$ has solutions $a$ and $b$. Then the pair $( a , b )$, is

Complex Numbers and Quadratic Equations

Solution:

$ x^2+a x+b=0$
$a+b=-a \Rightarrow 2 a+b=0 $
$\text { and } a b=b \Rightarrow b=0 (\text { rejected) } $
$\therefore a=1 ; b=-2 \Rightarrow (1,-2)$