Suppose an orbital may accomodate 3 electrons then the number of elements in IV period.

Question

Suppose an orbital may accomodate 3 electrons then the number of elements in IV period. (A) 18 (B) 27 (C) 12 (D) 45

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/cd7d58c102f8276dbd90b67932454e50-.png" /> no. of orbital =9 (one orbital occupy 3 electron) then no. of elements =9 × 3=27

Q. Suppose an orbital may accomodate $3$ electrons then the number of elements in $I V$ period.

18

27

12

45

no. of orbital $= 9$
(one orbital occupy $3$ electron)
then no. of elements $= 9 \times 3 = 27$

Q. Suppose an orbital may accomodate 3 electrons then the number of elements in IV period.

18

27

12

45

no. of orbital =9 (one orbital occupy 3 electron) then no. of elements =9×3=27

Q. Suppose an orbital may accomodate $3$ electrons then the number of elements in $I V$ period.

no. of orbital $= 9$
(one orbital occupy $3$ electron)
then no. of elements $= 9 \times 3 = 27$