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Chemistry
Suppose an orbital may accomodate 3 electrons then the number of elements in IV period.
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Q. Suppose an orbital may accomodate $3$ electrons then the number of elements in $IV$ period.
Classification of Elements and Periodicity in Properties
A
18
B
27
C
12
D
45
Solution:
no. of orbital $=9$
(one orbital occupy $3$ electron)
then no. of elements $=9 \times 3=27$