Suppose 0.5 mole of an ideal gas undergoes an isothermal expansion as energy is added to it as heat Q. Graph shows the final volume Vf versus Q. The temperature of the gas is (. use ln 9=2 and . R=(25/3) J / mol - K )

Question

Suppose 0.5 mole of an ideal gas undergoes an isothermal expansion as energy is added to it as heat Q. Graph shows the final volume Vf versus Q. The temperature of the gas is (. use ln 9=2 and . R=(25/3) J / mol - K ) (A) 293 K (B) 360 K (C) 386 K (D) 412 K

Tardigrade Admin · Accepted Answer

Q=W= n R T ln (Vf/Vi) T=(Q/n R ln Vf / Vi) =(1500/0.5 × 25 / 3 × ln 3) =(1500/0.5 × 25 / 3 × 1)=360 K

Q. Suppose $0.5$ mole of an ideal gas undergoes an isothermal expansion as energy is added to it as heat $Q$ . Graph shows the final volume $V_{f}$ versus $Q$ . The temperature of the gas is $($ use $ln 9 = 2$ and $R = \frac{25}{3} J / m o l - K)$

293 K

360 K

386 K

412 K

$Q = W = n RT ln \frac{V _{f}}{V _{i}}$
$T = \frac{Q}{n R l n V _{f} / V _{i}}$
$= \frac{1500}{0.5 \times 25/3 \times l n 3}$
$= \frac{1500}{0.5 \times 25/3 \times 1} = 360 K$

Q. Suppose 0.5 mole of an ideal gas undergoes an isothermal expansion as energy is added to it as heat Q. Graph shows the final volume Vf​ versus Q. The temperature of the gas is ( use ln9=2 and R=325​J/mol−K)