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Q. Suppose $0.5$ mole of an ideal gas undergoes an isothermal expansion as energy is added to it as heat $Q$. Graph shows the final volume $V_{f}$ versus $Q$. The temperature of the gas is $\left(\right.$ use $\ln 9=2$ and $\left. R=\frac{25}{3} J / mol - K \right)$Physics Question Image

Thermodynamics

Solution:

$Q=W= n R T \ln \frac{V_{f}}{V_{i}}$
$T=\frac{Q}{n R \ln V_{f} / V_{i}}$
$=\frac{1500}{0.5 \times 25 / 3 \times \ln 3}$
$=\frac{1500}{0.5 \times 25 / 3 \times 1}=360\, K$