Sun subtends an angle of 0.5° at the centre of curvature of a concave mirror of radius of curvature 15 m. The diameter of the image of the sum formed by the mirror is

Question

Sun subtends an angle of 0.5° at the centre of curvature of a concave mirror of radius of curvature 15 m. The diameter of the image of the sum formed by the mirror is (A) 8.55 cm (B) 7.55 cm (C) 6.55 cm (D) 5.55 cm

Tardigrade Admin · Accepted Answer

θ =(1/2)× (π /180) rad (d i a m e t a r o f i m a g e/f o c a l l e n g t h)=θ Or diameter of image =(1/2)× (π /180)× (15/2)× 100 cm=6.55 cm

Q. Sun subtends an angle of $0. 5^{\circ}$ at the centre of curvature of a concave mirror of radius of curvature 15 m. The diameter of the image of the sum formed by the mirror is

8.55 cm

7.55 cm

6.55 cm

5.55 cm

$θ = \frac{1}{2} \times \frac{π}{180}$ rad
$\frac{d iam e t a r o f ima g e}{f oc a l l e n g t h} = θ$
Or diameter of image
$= \frac{1}{2} \times \frac{π}{180} \times \frac{15}{2} \times 100 c m = 6.55 c m$

Q. Sun subtends an angle of 0.5∘ at the centre of curvature of a concave mirror of radius of curvature 15 m. The diameter of the image of the sum formed by the mirror is