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Q. Sun subtends an angle of $0.5^\circ $ at the centre of curvature of a concave mirror of radius of curvature 15 m. The diameter of the image of the sum formed by the mirror is

NTA AbhyasNTA Abhyas 2022

Solution:

$\theta =\frac{1}{2}\times \frac{\pi }{180} \, $ rad
$\frac{d i a m e t a r \, o f \, i m a g e}{f o c a l \, l e n g t h}=\theta $
Or diameter of image
$=\frac{1}{2}\times \frac{\pi }{180}\times \frac{15}{2}\times 100 \, cm=6.55 \, cm$