Strong reducing behavior of H 3 PO 2 is due to

Question

Strong reducing behavior of H 3 PO 2 is due to (A) Presence of 3 P - H bonds (B) Presence of two - OH groups and one P-H bond (C) Presence of one - OH group and two P-H bonds (D) High electron gain enthalpy of phosphorus

Tardigrade Admin · Accepted Answer

II > IV > III > I > V Two P-H groups will be oxidized to P-OH group. A species that get oxidized is a reducing agent.

Q. Strong reducing behavior of $H_{3} P O_{2}$ is due to

Presence of $3 P - H$ bonds

Presence of two - OH groups and one P-H bond

Presence of one - OH group and two P-H bonds

High electron gain enthalpy of phosphorus

II > IV > III > I > V Two P-H groups will be oxidized to P-OH group. A species that get oxidized is a reducing agent.

Q. Strong reducing behavior of H3​PO2​ is due to

Presence of 3P−H bonds

Presence of two - OH groups and one P-H bond

Presence of one - OH group and two P-H bonds

High electron gain enthalpy of phosphorus

II > IV > III > I > V Two P-H groups will be oxidized to P-OH group. A species that get oxidized is a reducing agent.

Q. Strong reducing behavior of $H_{3} P O_{2}$ is due to

Presence of $3 P - H$ bonds