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Chemistry
Strong reducing behavior of H 3 PO 2 is due to
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Q. Strong reducing behavior of $H _{3} PO _{2}$ is due to
A
Presence of $3 P - H$ bonds
B
Presence of two - OH groups and one P-H bond
C
Presence of one - OH group and two P-H bonds
D
High electron gain enthalpy of phosphorus
Solution:
II > IV > III > I > V Two P-H groups will be oxidized to P-OH group. A species that get oxidized is a reducing agent.