Strong base ( NaOH ) is being titrated with strong acid (HCl), variation of pH with volume of acid added is shown by

Question

Strong base ( NaOH ) is being titrated with strong acid (HCl), variation of pH with volume of acid added is shown by (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

NaOH (a strong base) has pH >7 As, HCl is added, NaOH is neutralised. NaOH + HCl leftharpoons NaCl + H 2 O Thus, basic solution ( pH >7) changes to neutral ( pH =7) and then to acidic solution ( pH <7) when excess of HCl is added.

Q. Strong base $(N a O H)$ is being titrated with strong acid $(H Cl)$ , variation of $p H$ with volume of acid added is shown by

$N a O H$ (a strong base) has $p H > 7$

As, $H Cl$ is added, $N a O H$ is neutralised.

$N a O H + H Cl ⇌ N a Cl + H_{2} O$

Thus, basic solution $(p H > 7)$ changes to neutral $(p H = 7)$ and then to acidic solution $(p H < 7)$ when excess of $H Cl$ is added.

Q. Strong base (NaOH) is being titrated with strong acid (HCl), variation of pH with volume of acid added is shown by

NaOH (a strong base) has pH>7 As, HCl is added, NaOH is neutralised. NaOH+HCl⇌NaCl+H2​O Thus, basic solution (pH>7) changes to neutral (pH=7) and then to acidic solution (pH<7) when excess of HCl is added.

Q. Strong base $(N a O H)$ is being titrated with strong acid $(H Cl)$ , variation of $p H$ with volume of acid added is shown by

$N a O H$ (a strong base) has $p H > 7$

As, $H Cl$ is added, $N a O H$ is neutralised.

$N a O H + H Cl ⇌ N a Cl + H_{2} O$

Thus, basic solution $(p H > 7)$ changes to neutral $(p H = 7)$ and then to acidic solution $(p H < 7)$ when excess of $H Cl$ is added.