Question

Strength of $H_2{O}_2$ is $15.18g{L}^{-1}$, then it is equal to

• A. 1 volume
• B. 10 volume
• C. 5 volume
• D. 7 volume

Answer 1

Answer: (C)

Volume strength $=\frac{5.6\times \text{ Strength in }g{L}^{-1}}{\text{ Eq. wt. of }{H}_2{O}_2}$

$=\frac{5.6\times 15.18}{12}=5$ volumes