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Q. Strength of $H_2O_2$ is $15.18\, g\, L^{-1}$, then it is equal to

AIIMSAIIMS 2013Hydrogen

Solution:

Volume strength $=\frac{5.6 \times \text { Strength in } g L^{-1}}{\text { Eq. wt. of } H _{2} O _{2}}$

$=\frac{5.6 \times 15.18}{12} =5$ volumes