Q.
Statement I The distance between the points P(1,−3,4) and Q(−4,1,2) is 5 units. Statement IIPQ=(x2−x1)2+(y2−y1)2+(z2−z1)2
where, P and Q are (x1,y1,z1) and (x2,y2,z2).
185
172
Introduction to Three Dimensional Geometry
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Solution:
The distancee PQ between the points P(1,−3,4) and Q(−4,1,2) is PQ=(−4−1)2+(1+3)2+(2−4)2 =25+16+4=45=35 units