Statement 1: CuSO4.5H2O on heating to 250°C loses all the five H2O molecules and becomes anhydrous Statement 2: All five H2O molecules are coordinated to the central Cu2+ ion.

Question

Statement 1: CuSO4.5H2O on heating to 250°C loses all the five H2O molecules and becomes anhydrous Statement 2: All five H2O molecules are coordinated to the central Cu2+ ion. (A) If both Statement 1 and Statement 2 are true and the statement 2 is the correct explanation o f the statement 1. (B) If both Statement 1 and Statement 2 are true but statement 2 is not the correct explanation o f the statement 1. (C) If Statement 1 is true but Statement 2 is false. (D) If Statement 1 is false but Statement 2 is true

Tardigrade Admin · Accepted Answer

Statement 1: CuSO4.5H2O(blue) xrightarrow250°C CuSO4(white) + 5H2O Anhydrous copper sulphate becomes white because there is no d-d transition of electron in absence of ligands according to crystal field theory. Statement 2: Four water molecules are coordinated to Cu2+ and fifth one is hydrogen bonded to two water molecules and anion, SO2-4

Q. Statement 1: CuSO4​.5H2​O on heating to 250∘C loses all the five H2​O molecules and becomes anhydrous Statement 2: All five H2​O molecules are coordinated to the central Cu2+ ion.

If both Statement 1 and Statement 2 are true and the statement 2 is the correct explanation o f the statement 1.

If both Statement 1 and Statement 2 are true but statement 2 is not the correct explanation o f the statement 1.

If Statement 1 is true but Statement 2 is false.

If Statement 1 is false but Statement 2 is true

Q. Statement 1: $C u S O_{4} .5 H_{2} O$ on heating to $25 0^{\circ} C$ loses all the five $H_{2} O$ molecules and becomes anhydrous
Statement 2: All five $H_{2} O$ molecules are coordinated to the central $C u^{2 +}$ ion.