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Q. Statement 1: $CuSO_4.5H_2O$ on heating to $250^{\circ}C$ loses all the five $H_2O$ molecules and becomes anhydrous
Statement 2: All five $H_2O$ molecules are coordinated to the central $Cu^{2+}$ ion.

The d-and f-Block Elements

Solution:

Statement 1: $CuSO_4.5H_2O(blue) \xrightarrow{250^{\circ}C} CuSO_4(white) + 5H_2O$ Anhydrous copper sulphate becomes white because there is no d-d transition of electron in absence of ligands according to crystal field theory.
Statement 2: Four water molecules are coordinated to $Cu^{2+}$ and fifth one is hydrogen bonded to two water molecules and anion, $SO^{2-}_4$