Statement 1: An em wave going through vaccum is described as E=E0 sin (k x-ω t) and B=B0 sin (k x- ω t ) has ω E0=k B0 Statement 2: For an em wave, c=E0 / B0.

Question

Statement 1: An em wave going through vaccum is described as E=E0 sin (k x-ω t) and B=B0 sin (k x- ω t ) has ω E0=k B0 Statement 2: For an em wave, c=E0 / B0. (A) Statement -1 is true, Statement -2 is false (B) Statement -1 is false, Statement -2 is true (C) Statement -1 is true, Statement -2 is true and Statement -2 is a correct explanation for Statement -1. (D) Statement -1 is true, Statement -2 is true but Statement -2 is not a correct explanation for Statement -1.

Tardigrade Admin · Accepted Answer

Statement -1 is false, Statement - 2 is true As (E0/B0)=c=(ω/k) ⇒ k E0=ω B0

Q. Statement 1: An em wave going through vaccum is described as $E = E_{0} sin (k x - ω t)$ and $B = B_{0} sin (k x -$ $ω t$ ) has $ω E_{0} = k B_{0}$
Statement 2 : For an em wave, $c = E_{0} / B_{0}$ .

Statement $- 1$ is true, Statement $- 2$ is false

Statement $- 1$ is false, Statement $- 2$ is true

Statement $- 1$ is true, Statement $- 2$ is true and Statement $- 2$ is a correct explanation for Statement $- 1.$

Statement $- 1$ is true, Statement $- 2$ is true but Statement $- 2$ is not a correct explanation for Statement $- 1.$

Statement $- 1$ is false, Statement $- 2$ is true
As $\frac{E _{0}}{B _{0}} = c = \frac{ω}{k} \Rightarrow k E_{0} = ω B_{0}$

Q. Statement 1: An em wave going through vaccum is described as E=E0​sin(kx−ωt) and B=B0​sin(kx− ωt ) has ωE0​=kB0​ Statement 2 : For an em wave, c=E0​/B0​.

Statement −1 is true, Statement −2 is false

Statement −1 is false, Statement −2 is true

Statement −1 is true, Statement −2 is true and Statement −2 is a correct explanation for Statement −1.

Statement −1 is true, Statement −2 is true but Statement −2 is not a correct explanation for Statement −1.