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Q. Statement 1: An em wave going through vaccum is described as $E=E_{0} \sin (k x-\omega t)$ and $B=B_{0} \sin (k x-$ $\omega t$ ) has $\omega E_{0}=k B_{0}$
Statement 2 : For an em wave, $c=E_{0} / B_{0}$.

Communication Systems

Solution:

Statement $-1 $ is false, Statement $- 2$ is true
As $\frac{E_{0}}{B_{0}}=c=\frac{\omega}{k} \Rightarrow k E_{0}=\omega B_{0}$