Standing waves are produced in 10 m long stretched string. If the string vibrates in 5 segments and wave velocity is 20 m/s, its frequency is

Question

Standing waves are produced in 10 m long stretched string. If the string vibrates in 5 segments and wave velocity is 20 m/s, its frequency is (A) 5 Hz (B) 4 Hz (C) 2 Hz (D) 10 Hz

Tardigrade Admin · Accepted Answer

The frequency of standing wave v =(P/2 l) √(T/m) or v =(P/2 l) v=(5 × 20/2 × 10)=5 Hz

Q. Standing waves are produced in $10 m$ long stretched string. If the string vibrates in $5$ segments and wave velocity is $20 m / s$ , its frequency is

5 Hz

4 Hz

2 Hz

10 Hz

The frequency of standing wave
$v = \frac{P}{2 l} \frac{T}{m}$
or $v = \frac{P}{2 l} v = \frac{5 \times 20}{2 \times 10} = 5 Hz$

Q. Standing waves are produced in 10m long stretched string. If the string vibrates in 5 segments and wave velocity is 20m/s, its frequency is