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  4. Standing waves are produced in 10 m long stretched string. If the string vibrates in 5 segments and wave velocity is 20 m/s, its frequency is

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Q. Standing waves are produced in $10\, m$ long stretched string. If the string vibrates in $5$ segments and wave velocity is $20\,m/s$, its frequency is

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Solution:

The frequency of standing wave
$v =\frac{P}{2 l} \sqrt{\frac{T}{m}} $
or $v =\frac{P}{2 l} v=\frac{5 \times 20}{2 \times 10}=5\, Hz$