Standard electrode potentials for Fe electrode are given as Fe2++2e- arrow Fe ; Eo=-0.44 V Fe3++e- arrow Fe2+; Eo=+0.77 V Fe2+, Fe3+ and Fe blocks are kept together then

Question

Standard electrode potentials for Fe electrode are given as Fe2++2e- arrow Fe ; Eo=-0.44 V Fe3++e- arrow Fe2+; Eo=+0.77 V Fe2+, Fe3+ and Fe blocks are kept together then (A) Fe 3+ decreases (B) Fe 3+ increases (C) ( Fe 2+/ Fe 3+) remains unchanged (D) Fe 2+ decreases

Tardigrade Admin · Accepted Answer

The metals have higher negative values of their electrode potential can displace metals having lower values from their salt solution. So, Fe 3+ decreases.

Q. Standard electrode potentials for $F e$ electrode are given as
$F e^{2 +} + 2 e^{-} \to F e; E^{o} = - 0.44 V$
$F e^{3 +} + e^{-} \to F e^{2 +}; E^{o} = + 0.77 V$
$F e^{2 +}, F e^{3 +}$ and $F e$ blocks are kept together then

$F e^{3 +}$ decreases

$F e^{3 +}$ increases

$\frac{F e ^{2 +}}{F e ^{3 +}}$ remains unchanged

$F e^{2 +}$ decreases

The metals have higher negative values of their electrode potential can displace metals having lower values from their salt solution. So, $F e^{3 +}$ decreases.

Q. Standard electrode potentials for Fe electrode are given as Fe2++2e−→Fe;Eo=−0.44V Fe3++e−→Fe2+;Eo=+0.77V Fe2+,Fe3+ and Fe blocks are kept together then

Fe3+ decreases

Fe3+ increases

Fe3+Fe2+​ remains unchanged

Fe2+ decreases