Tardigrade
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Tardigrade
Question
Physics
Specific heat of a gas undergoing adiabatic change is
Q. Specific heat of a gas undergoing adiabatic change is
2012
169
AMU
AMU 2002
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A
zero
B
infinite
C
positive
D
negative
Solution:
If during a process taking place in a system, heat
(
Q
)
neither enters the system nor leaves it, then the process is adiabatic that is
Q
=
0
.
From the formula of specific heat, we have
c
=
m
Δ
T
Q
For adiabatic change
Q
=
0
∴
c
=
0