Question

Species like $SbC{l}_6^{-},SnC{l}_6^{2-},Xe{F}_5^{+}$ and $I{O}_6^{5-}$ has hybridisation as $s{p}^3{d}^{x-1}.$ The value of ''x'' is

Answer 1

Answer: 3.00

Finding the number of hybridized orbitals (by using the formula) in the central atom to find the hybridization:

Finding the number of hybridized orbitals (by using the formula) in the central atom to find the hybridization:

$\mathrm{H}=\frac{1}{2}(\mathrm{V}+\mathrm{M}-\mathrm{C}+\mathrm{A})$
${\mathrm{SbCl}}_6-\Rightarrow \mathrm{H}=\frac{1}{2}(5+6+1)=6,{\mathrm{sp}}^3{\mathrm{d}}^2$
${\mathrm{SnCl}}_6^{2-}\Rightarrow \mathrm{H}=\frac{1}{2}(4+6+2)=6,{\mathrm{sp}}^3{\mathrm{d}}^2$
${\mathrm{XeF}}_5+\mathrm{H}=\frac{1}{2}(8+5-1)=6,{\mathrm{sp}}^3{\mathrm{d}}^2$
${\mathrm{IO}}_{6}5-\mathrm{H}=\frac{1}{2}(7+0+5)=6,{\mathrm{sp}}^3{\mathrm{d}}^2$