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Chemistry
Species like SbCl6-,SnCl62-, XeF5+ and IO5-6 has hybridisation as sp3dx-1. The value of ''x'' is
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Q. Species like $SbCl_6^-,SnCl_6^{2-}, XeF_5^+$ and $IO^{5-}_{6}$ has hybridisation as $sp^3d^{x-1}.$ The value of ''x'' is
NTA Abhyas
NTA Abhyas 2020
Chemical Bonding and Molecular Structure
A
B
C
D
Solution:
Finding the number of hybridized orbitals (by using the formula) in the central atom to find the hybridization:
Finding the number of hybridized orbitals (by using the formula) in the central atom to find the hybridization:
$\mathrm{H}=\frac{1}{2}(\mathrm{~V}+\mathrm{M}-\mathrm{C}+\mathrm{A})$
$\mathrm{SbCl}_{6}-\Rightarrow \mathrm{H}=\frac{1}{2}(5+6+1)=6, \mathrm{sp}^{3} \mathrm{~d}^{2}$
$\mathrm{SnCl}_{6}^{2-} \Rightarrow \mathrm{H}=\frac{1}{2}(4+6+2)=6, \mathrm{sp}^{3} \mathrm{~d}^{2}$
$\mathrm{XeF}_{5}+\mathrm{H}=\frac{1}{2}(8+5-1)=6, \mathrm{sp}^{3} \mathrm{~d}^{2}$
$\mathrm{IO}_{6} 5-\mathrm{H}=\frac{1}{2}(7+0+5)=6, \mathrm{sp}^{3} \mathrm{~d}^{2}$