Question

Species having the same bond order are (1) $N_2^{2-}$ (2) $N_2^{+}$ (3) $N_2$ (4) $N_2^{-}$

• A. 1, 2 and 3 are correct
• B. 1 and 2 are correct
• C. 2 and 4 are correct
• D. 1 and 3 are correct

Answer 1

Answer: (C)

BO of $N_2^{2-}=\frac{1}{2}(10-6)=2$
BO of $N_2^{+}=\frac{1}{2}(9-4)=2.5$
BO of $N_2=\frac{1}{2}(10-4)=3$
BO of $N_2^{-}=\frac{1}{2}(10-5)=2.5$
Hence, bond order of $N_2^{+}$ and $N_2^{-}$ are same.