Question

Species having the same bond order are (1) $ N_{2}^{2-} $ (2) $ N_{2}^{+} $ (3) $ {{N}_{2}} $ (4) $ N_{2}^{-} $

• A. 1, 2 and 3 are correct
• B. 1 and 2 are correct
• C. 2 and 4 are correct
• D. 1 and 3 are correct

Answer 1

Answer: (C)

BO of $ N_{2}^{2-}=\frac{1}{2}(10-6)=2 $
BO of $ N_{2}^{+}=\frac{1}{2}(9-4)=2.5 $
BO of $ {{N}_{2}}=\frac{1}{2}(10-4)=3 $
BO of $ N_{2}^{-}=\frac{1}{2}(10-5)=2.5 $
Hence, bond order of $ N_{2}^{+} $ and $ N_{2}^{-} $ are same.